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[tex] (1\frac{1}{3}x+2\frac{2}{5})(1\frac{1}{5}x-1\frac{2}{3})=(1\frac{2}{3}x+1\frac{1}{5})(1\frac{2}{5}x-3\frac{1}{3}) [/tex]

8/5 *х²-20/9 *х+72/25 *х-4=7/3 *х²-50/9 *х +42/25 *х-4

8/5 *х²-20/9 *х+72/25 *х=7/3 *х²-50/9 *х +42/25 *х

8/5 *х²+148/225 *х=7/3 *х²-872/225 *х

8/5 *х²+148/225 *х-7/3 *х²+872/225 *х=0

-11/15 *х²+68/15 *х=0

-1/15 *х*(11х-68)=0

х(11х-68)=0

х=0            11х-68=0

                  11х=68

                  х= 6 8/11

Ответ: х1=0

             х2=6 8/11