площадь поверхности прямой треугольной призмы равна 368 см2 стороны основания равны 4 см, 13см, 15см найдите высоту призмы

площадь поверхности прямой треугольной призмы равна 368 см2 стороны основания равны 4 см, 13см, 15см найдите высоту призмы
- Предмет:
  Математика
- Автор:
  dulce4yrx
- 5 лет назад

Ответы 1

Sполн = Sбок + 2SоснSбок = Sполн - 2SоснSосн = $\sqrt{p(p - a)(p - b)(p - c)}$ p = (a + b + c)/2 = (4 + 13 + 15)/2 = 16Sосн = $\sqrt{16(16 - 4)(16 - 13)(16 - 15)} = \sqrt{16 \times 12 \times 3 \times 1} = \sqrt{16 \times 4 \times 3 \times 3 \times 1} = \sqrt{16 \times 4 \times 9} = 4 \times 2 \times 3 = 24$ Sбок = 368 - 2*24 = 320 (см2)Pосн*H = 32032*H = 320H = 10 (см)Ответ: 10 см.
- Автор:
  javier62
- 5 лет назад
- 0
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площадь поверхности прямой треугольной призмы равна 368 см2 стороны основания равны 4 см, 13см, 15см найдите высоту призмы

Ответы 1

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