1/x-3+1/x+3=5/8 помогите пожалуйста решить

1/(х-3) + 1/(х+3) = 5/8,

(х+3)/(х+3)(х-3) + (х-3)/(х+3)(х-3) = 5/8,

2х/(х²-9) = 5/8,

2х * 8 = 5 * (х²-9),

16х = 5х² - 45,

5х² - 16х - 45 = 0,

Д = (-16)² - 4*5*(-45) = 256 + 900 = 1156,

х1 = (16 + 34)/2*5 = 50/10 = 5,

х2 = (16 - 34)/2*5 = -18/10 = -1,8