(4х-3)(5х+8)=0,(-7х+4)(8x-9)=0 пж помогите

(4x-3)(5x+8)=04x-3=05x+8=0x=3/4=0,75x=-8/5=-1,6x1=-1,6x2=0,75(-7x+4)(8x-9)=0-7x+4=08x-9=0x=4/7x=9/8=1,125x1=4/7x2=1,125

1) (4х-3)(5х+8)=0

4х-3=0

5х+8=0

х1=-8/5

x2=3/4

2) (-7х+4)(8х-9)=0

-7х+4=0

8х-9=0

х1=4/7

х2=9/8