Как решить:
2+3i/5-2i
i-1/i+1

=(2+3i)(5+2i)/(5-2i)(5+2i)=(10+4i+15i+6i²)/(25-4i²)=(4+19i)/292)=(i-1)(i-1)/(i+1)(i-1)=(i²-i-i+1)/(i²-1)=2i/2=i(i²=-1)