Помогите с логорифмами
log(3) x=4log(3) 3-2log(3) 4

log(3)x=4+log(3)4^-2log(3)x=log(3)3^4+log(3)4^-2log(3)x=log(3)3^4*4^-2log(3)x=log(3)81*1(4^2)log(3)x=log(3)81/16x=81/16x=5,1/16

log(3) x = 4log(3) 3 - 2log(3) 4

x>0

log(3) x = log(3) 3^4 - log(3) 4^2

log(3) x = log(3) 3^4/4^2

x = 3^4/4^2 = 81/16 = 5 1/16

k log(a) b = log(a) a^k

log(a) b - log(a) c = log(a) b/c