Log(3x-6)-Log2*3=Log2*3

Решение

log₂(3x–6 ) – log₂ 3 = log₂ 3

ОДЗ: 3x - 6 > 0

3x > 6

x > 2

D(y) = (2; + ∞)  

log₂(3x–6 ) = 2 log₂ 3  

log₂(3x–6 ) = log₂ 3²  

3x - 6 = 9

3x = 9 + 6

3x = 15

x = 5 ∈ (2; + ∞)  

Ответ: x = 5