в треугольнике ABC угол C равен 90, sinA=√17/17. Найдите tgA

в треугольнике ABC угол C равен 90, sinA=√17/17. Найдите tgA
- Предмет:
  Математика
- Автор:
  waylonserrano
- 6 лет назад

Ответы 1

Ответ:
tg∠A=1/4
Пошаговое объяснение:
sin∠A=√17/17 = BC/AB
BC - противолежащий катет, равен √17, АВ - гипотенуза, равна 17
tg∠A=BC/AC
AC - прилежащий катет, находим его по теореме Пифагора:
AB² = AC² + BC²
AC² = AB² - BC² = 17² - (√17)² = 289 - 17 = 272
AC = √272
tg∠A = √17 / √272 = √(17/272) = √(1/16) = 1/4
- Автор:
  dayami2rav
- 6 лет назад
- 0
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в треугольнике ABC угол C равен 90, sinA=√17/17. Найдите tgA

Ответы 1

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