[tex]a)2 {x}^{2} + 3x - 5 = 0[/tex]
[tex] b)\frac{27}{x + 5} - \frac{ 1}{x - 5} = 0[/tex]

a) 2x²+3x-5 = 0

D = 9+4*2*5 = 49 = 7²

x1 = (-3-7)/4 = -10/4 = -2 1/2

x2 = (-3+7)/4 = 1

b) 27/(x+5)-1/(x-5) = 0

О.Д.З.: x ≠ ±5

(27x-135-x-5)/(x²-25) = 0

x²-25 ≠ 0 по ОДЗ.

26x-140 = 0

26x = 140

x = 5 5/13