Дано AB⟂a, CD=10√2, ∠CAD=90°, AC=AD. Найдите BD.

AC^2 + AD^2 = CD^2AC = AD -------------> 2*AD^2 = CD^2 --------> AD = V(CD^2\2) = CD\V2 = 10V2\V2 = 10BD^2 + AB^2 = AD^2BD^2 = AD^2 - AB^2 = 10^2 - 8^2 = 6^2 ------> BD = 6