«Логарифмирование и потенцирование» СРОЧНО надо

7) log(b) a = 2 -----> b^2 = a или a = b^2log(Va \ b^(1\3)) a^2 == 2 * 1\log2 (Va * b^(1\3)) = = 2 \ [log2 (Va) + log2 (b^(1\3)) == 2 \ (1\2 * log2 a + 1\3 * log2 b) == 2 \ (1\2 * log2 (b^2) + 1\3 * log2 b) == 2 \ (1\2 * 2 * log2 b + 1\3 * log2 b) == 2 \ (log2 b + 1\3 * log2 b) =\= 2 \ (4\3 * log2 b) = = 6\4 * log2 b = 3\2 * log2 b6) log5 15 = log5 5 + log5 3 = 1 + blog5 12 = log5 4 + log5 3 = 2*log5 2 + log5 3 = 2a + b5) log3 x = 2*log9 6 - log9 12 -----> оДЗ: x > 0log3 x = log9 (6^2 \ 12)log3 x = log(3^2) 3log3 x = 1\2 * log3 3log3 x = 1\2x = 3^(1\2)= V3