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1) 1 - 2cosx = 0cosx = 1/2x = ± П/3 + 2Пn, n€Z2){sin^4x+ cos^4 x- 0,625 = 0{ 1 - 2cosx ≥ 0, cosx ≤ 1/2sin^4 x+ cos^4 x- 0,625 = 0 (1-cos2x)^2/ 4 +(1+cos2x)^2/ 4 - 0,625=0(2+2cos^2 2x)/ 4 - 0, 625=02cos^2 2x =1/21+ cos 4x=1/2cos4x=-1/24x=±2П/3 + 2Пk, k €Zx=±П/6 + Пk/2, k €Z{ x=±П/6 + Пk/2, k €Z{cosx ≤ 1/2x=±2П/3 +2Пm,m€Zotv/x= ± П/3 + 2Пn, n€Zx=±2П/3 +2Пm,m€Z

sin^4 + cos^4 - 0,625 = 0(sin² + cos²)² - 2sin²x cos²x -0,625=0(1)² - 1/2 (2sinxcosx)² - 0,625 = 01 - 1/2sin²2x - 0,625 = 00,375 - 1/2sin²2x = 0sin²2x = 0,75 = 3/4sin2x = ± v3/2 ≈ ± 0,87ОДЗ: cosx <= 1/2Х = ………… 2) 1 - 2cosx = 0cosx = 1/2x = ± pi/3 + 2pik, k€Z