Log4((x+2)(x+3))+log4*x-2/x+3=2 Помогите решить

Log 4 ( ( x + 2 ) * ( x + 3 ) ) + log 4 ( x - 2 / x + 3 ) = 2 Log 4 ( ( x + 2 ) * ( x + 3 ) * ( x - 2 / x + 3 ) ) = 2 ( ( x + 2 ) * ( x + 3 ) * ( x - 2 / x + 3 ) ) = 4 ^ 2 ( x + 2 ) * ( x + 3 ) * ( x * х - 2 + 3 * х ) = 16 * х( х * х + 5 * х + 6 ) ( х * х - 2 + 3 * х ) - 16 * х = 0 x ^ 4 - 2 * x ^ 2 + 3 * x ^ 3 + 5 * x ^ 3 - 10 * x + 15 * x ^ 2 + 6 * x ^ 2 - 12 + 18 * x - 16 * x = 0 x ^ 4 + 8 * x ^ 3 + 19 * x ^ 2 - 8 * x- 12 = 0 отсюда х1 = - 4 , 08 + 2 , 06 * ix2 = - 4 . 0 8 - 2 . 0 6 * ix3 = 0 . 84 x4 = - 0 . 68