Помогите решить уравнения пож3а²-6аб+3б² Ах²+4ах+4а А²б-4абс+4 бс² 2х²-4Х+2 -5а²-10аб-5б² -3х²+12х-12 -а²+10аб-25б² -12х³-12х²-3х

3a² - 6ab + 3b² = 3(a² - 2ab + b²) = 3(a - b)²ax² + 4ax + 4a = a(x² + 4x + 4) = a(x² + 2 * x * 2 + 2²) = a(x + 2)²a²b- 4abc + 4bc² = b(a² - 4ac + 4c²) = b(a² - 2 *a * 2c + (2c)²) = b(a - 2c)²2x² - 4x + 2 = 2(x² - 2x + 1) = 2(x² - 2 * x * 1 + 1²) = 2(x - 1)²- 5a² - 10ab - 5b² = - 5(a² + 2ab + b²) = - 5(a + b)² - 3x² + 12x - 12 = - 3(x² - 4x + 4) = - 3(x² - 2 * x * 2 + 2²) = - 3(x - 2)²- а² + 10ab - 25b² = - (а² - 10ab + 25b²) = - (а² - 2 *a * 5b + (5b)²) = - (a - 5b)²- 12x³ - 12x² - 3x = - 3x(4x² + 4x + 1) = - 3x((2x)² + 2 * 2x * 1 + 1²) = - 3x(2x + 1)²