Решите уравнение (х^2-5х-2)^2=(х^2-4х+2)^2

(х^2-5х-2)^2=(х^2-4х+2)^2 ; ( x ^ 2 - 5 * x - 2 ) ^ 2 - ( x ^ 2 - 4 * x + 2 ) ^ 2 = 0 ; ( x ^ 2 - 5 * x - 2 - ( x ^ 2 - 4 * x + 2 ) ) * ( x ^ 2 - 5 * x - 2 + x ^ 2 - 4 * x + 2 ) = 0 ; ( x ^ 2 - 5 * x - 2 - x ^ 2 + 4 * x - 2 ) ) * ( x ^ 2 - 5 * x - 2 + x ^ 2 - 4 * x + 2 ) = 0 ; ( x ^ 2 - 5 * x - 2 - x ^ 2 + 4 * x - 2 ) ) * ( x ^ 2 - 5 * x - 2 + x ^ 2 - 4 * x + 2 ) = 0 ; ( - 5 * x - 2 + 4 * x - 2 ) * ( 2 * x ^ 2 - 9 * x ) = 0 ; ( - x - 4 ) * x * ( 2 * x - 9 ) = 0 ; 1 ) - x - 4 = 0 ; x = - 4 ; 2 ) x = 0 ; 3 ) 2 *x - 9 = 0 ; x = 9 / 2 ; x = 4.5 ; Ответ: х = 0, х =- 4 , х = 4,5.