Помогите решить: x^6=(6x-8)^3

x ^ 6 = ( 6 * x - 8 ) ^ 3 ; x ^ 6 - ( 6 * x - 8 ) ^ 3 = 0 ; ( x ^ 2 ) ^ 3 - ( 6 * x - 8 ) ^ 3 = 0 ; ( x ^ 2 - 6 * x + 8 ) * ( x ^ 4 + 2 * x ^ 2 * ( 6 * x - 8 ) + 8 ^ 2 ) = 0 ; ( x ^ 2 - 6 * x + 8 ) * ( x ^ 4 + 12 * x ^ 3 - 16 * x ^ 2 + 64 ) = 0 ; 1 ) x ^ 2 - 6 * x + 8 = 0 ; D = b ^ 2 - 4ac = (-6) ^ 2 - 4·1·8 = 36 - 32 = 4 ;x1 = ( 6 - √4 ) / ( 2·1 ) = ( 6 - 2 ) / 2 = 4 / 2 = 2 ;x2 = ( 6 + √4 ) / ( 2·1 ) = ( 6 + 2 ) / 2 = 8 / 2 = 4 ;2 ) x ^ 4 + 12 * x ^ 3 - 16 * x ^ 2 + 64 = 0 ; x = -1.43 ; x = - 13.19.