√(х+4) - √(6-х) = 2 решите пожалуйста

√ ( х + 4 ) - √ ( 6 - х ) = 2 ; ( √ ( х + 4 ) - √ ( 6 - х ) ) ^ 2 = 2 ^ 2 ; x + 4 - 2 * √ ( x + 4 ) * √ ( 6 - x ) + 6 - x = 4 ; 10 - 2 * √ ( x + 4) * √ ( 6 - x ) = 4 ; 6 = 2 * √ ( x + 4 ) * ( 6 - x ) ; 3 = √ ( x + 4 ) * ( 6 - x ) ; 9 = ( x + 4) * ( 6 - x ) ; 9 = 6 * x - x ^ 2 + 24 - 4 * x ; 9 = 2 * x - x ^ 2 + 24 ; 9 - 2 * x + x ^ 2 - 24 = 0 ; x ^ 2 - 2 * x - 15 = 0 ; D = b ^ 2 - 4 * a * c = ( - 2 ) ^ 2 - 4 * 1 * ( - 15 ) = 4 + 60 = 64 ;x1 = ( 2 - √64 ) / ( 2·1 ) = ( 2 - 8 ) / 2 = - 6 / 2 = - 3 ; x2 = ( 2 + √64 ) / ( 2·1 ) = ( 2 + 8 ) / 2 = 10 / 2 = 5 ; Ответ: х = - 3 и х = 5.