Решите пожалуйста задачу, срочно! 9^(2√x)=3^(2x-6)

9 ^ ( 2 * √ x ) = 3 ^ ( 2 * x - 6 ) ; ( 3 ^ 2 ) ^ ( 2 * √ x ) = 3 ^ ( 2 * x - 6 ) ; 3 ^ ( 2 * ( 2 * √ x ) ) = 3 ^ ( 2 * x - 6 ) ; 2 * ( 2 * √ x ) = 2 * x - 6 ; 2 * 2 * √ x = 2 * x - 6 ; 4 * √ x = 2 * x - 6 ; ( 4 * √ x ) ^ 2 = ( 2 * x - 6 ) ^ 2 ; 16 * x = 4 * x ^ 2 - 2 * 2 * x * 6 + 36 ; 16 * x = 4 * x ^ 2 - 24 * x + 36 ; 4 * x ^ 2 - 24 * x - 16 * x + 36 = 0 ; 4 * x ^ 2 - 40 * x + 36 = 0 ; 4 * ( x ^ 2 - 10 * x + 9 ) = 0 ; x ^ 2 - 10 * x + 9 = 0 ; D = b ^ 2 - 4ac = (-10) ^ 2 - 4·1·9 = 100 - 36 = 64 ;x1 = ( 10 - √64) / ( 2·1 ) = ( 10 - 8 ) / 2 = 2 / 2 = 1 ;x2 = ( 10 + √64 ) / ( 2·1 ) = ( 10 + 8 ) / 2 = 18 / 2 = 9 ; Ответ: х = 1 и х = 9.