Найти первую производную функции y=(3x+5)tg(2x-7)

y = (3 * x + 5) * tg (2 * x - 7);y \' = ((3 * x + 5) * tg (2 * x - 7)) \' = (3 * x + 5) \' * tq (2 * x - 7) + (tq (2 * x - 7)) \' * (3 * x + 5) = 3 * tq (2 * x - 7) + (1/cos ^ 2 (2 * x - 7) * (2 * x - 7) \' * (3 * x + 5) = 3 * tq (2 * x - 7) + (1/cos ^ 2 (2 * x - 7) * 2 * (3 * x + 5) = 3 * tq (2 * x - 7) + (2/cos ^ 2 (2 * x - 7) * * (3 * x + 5);В итоге получили, y \' = 3 * tq (2 * x - 7) + (2/cos ^ 2 (2 * x - 7) * * (3 * x + 5).