Решить неравенство: 1) 4x²+x-3/ 5x²-9x-2 <0 2)2+9x-5x²/ 3x²-2x-1 ≥0

1) (4x^2 + x - 3) / (5x^2 - 9x - 2) < 0;4x^2 + x - 3 = 0;D = 1 + 48 = 49;x1 = ( - 1 - 7) / 8 = - 1 и x2 = ( - 1 + 7) / 8 = 0,75;5x^2 - 9x - 2 = 0;D = 81 + 40 = 121;x1 = (9 - 11) / 10 = - 0,2 и x2 = (9 + 11) / 10 = 2;+ _ + _ +-------------[-1]-------------(-0,2)----------[0,75]---------(2)---------------x є [-1;-0,2) и [0,75;2);2)(2 + 9x - 5x^2) / (3x^2 - 2x - 1) ≥ 0;5x^2 - 9x - 2 = 0;D = 81 + 40 = 121;x1 = (9 - 11) / 10 = - 0,2 и x2 = (9 + 11) / 10 = 2;3x^2 - 2x - 1 = 0;D = 4 + 12 = 16;x2 = (2 - 4) / 6 = - 1/3 и x2 = (2 + 4) / 6 = 1;_ + _ + _---------------(-1/3)------------[-0,1]---------------(1)-----------------[2]-----------x є (-1/3;-0,1] и (1;2].