Решите систему уравнений {-x-y=3 {x^2+y^2=5

{ -x - y = 3; | * (-1); x^2 + y^2 = 5.{ x + y = -3; | - y; x^2 + y^2 = 5.{ x = -3 - y; | - y; x^2 + y^2 = 5.(-3 - y)^2 + y^2 = 5.y^2 + 6y + 9 + y^2 = 5.2y^2 + 6y + 9 - 5 = 0.2y^2 + 6y + 4 = 0. | : 2y^2 + 3y + 2 = 0.D = b^2 - 4ac = 9 - 8 = 1.y1 = (-3 + 1) / 2 = -1.y2 = (-3 - 1) / 2 = -2.x1 - 1 = -3.x1 = -3 + 1.x1 = -2.x2 - 2 = -3.x2 = -3 + 2.x2 = -1.Ответ: (-2; -1); (-1; -2).