1) 11 * 6^log 6(2) 2) loga* (ab^3), если log b (a) = 1/7

Тема: 1) 11 * 6^log 6(2) 2) loga* (ab^3), если log b (a) = 1/7Решение:1) 11 * 6^log 6(2)=11*2(6^log 6)=11*2*1=222) loga* (ab^3), если log b (a) = 1/7loga* (ab^3)= loga(a)+loga(b^3)= 1+3loga(b)log b (a) = 1/71/log(a)b=1/7log(a)b=71+3loga(b)=1+3*7=1+21=22