2sinx= -1 2cos2x= -2 из кореня 2 sinx=1 sin 2x=1 sin x/2 = 1 2sin x/2=1

1. 2sinx = -1;sinx = -1/2;x = (-1)^n * arcsin (-1/2) + pi * n, n ∈ Z;x = (-1)^n * 7pi/6 + pi * n, n ∈ Z.2. 2cos2x = -2 sqrt2;cos2x = -sqrt2;2x = +- arccos (-sqrt2) + 2pi * n, n ∈ Z;x = +- arccos (-sqrt2/2) + pi * n, n ∈ Z;x = +- 3pi/4 + pi * n, n ∈ Z.3. sinx=1;x = pi/2 + 2pi * n, n ∈ Z.4. sin 2x=1;2х = pi/2 + 2pi * n, n ∈ Z;x = pi/4 + pi * n, n ∈ Z.5. sin x/2 = 1;x/2 = pi/2 + 2pi * n, n ∈ Z;x = pi + 4 pi * n, n ∈ Z.6. 2sin x/2=1;sin x/2 = 1/2;x/2 = (-1)^n * arcsin 1/2 + pi * n, n ∈ Z;x/2 = (-1)^n * pi/6 + pi * n, n ∈ Z;x = (-1)^n * pi/3 + 2pi * n, n ∈ Z.