Log(9x) 27 = 1/log(3) x

log(9x) 27 = 1/log(3) x;log(3) 27/log(3) 9x = 1/log(3) x;log (3) 3^3/log(3) 9x = 1/log(3) x;3/log(3) 9x = 1/log(3) x;3log(3) x = log(3) 9x;3log(3) x = log(3) 9 + log(3) x;3log(3) x - log(3) x = log(3) 3^2;2log(3) x = 2;log(3) x = 1;3^1 = x;x = 3.Ответ: 3.