Решить уравнение : по теме -уравнения сводящиеся к квадратным 1)2/x-5 +14/x=3 2)40/x-2 - 40/x=1

1) 2/(x - 5) + 14/x = 3;(2x + 14(x - 5))/x(x - 5) = 3;2x + 14(x - 5) = 3x (x - 5);2x + 14x - 70 = 3x^2 - 15x;16x - 70 - 3x^2 + 15x = 0;-3x^2 + 31x - 70 = 0;D = 31^2 - 4 * (-3) * (-70) = 121;x1 = (-31 + 11)/(2 * (-3)) = 3 1/3;x2 = (-31 - 11)/(2 * (-3)) = 7.Ответ: 3 1/3, 7.2) 40/(x - 2) - 40/x = 1;(40x - 40(x - 2))/(x(x - 2)) = 1;40x - 40(x - 2) = x(x - 2);40x - 40x + 80 = x^2 - 2x;x^2 - 2x - 80 = 0;D = 4 + 320 = 324;x1 = (2 + 18)/2 = 1 + 9 = 10;x2 = (2 - 18)/2 = -16/2 = -8.Ответ: -8, 10.