Приведите уравнениe к виду ax²+bx+c=0 1)(2x-1)(2x+1)=x(2x+3) 2)(x+1)(x+2)=(2x-1)(x-2) 3)(x+3)(3x-2)=(4x+5)(2x-3)

ax²+bx+c=0

1)(2x - 1)(2x + 1) = x(2x + 3);

(2x)^2 - 1^2 = 2x^2 + 3x;

4x^2 - 1 - 2x^2 - 3x = 0;

2x^2 - 3x - 1 = 0;

2)(x + 1)(x + 2) = (2x - 1)(x - 2);

x^2 + 2x + x + 2 = 2x^2 - 4x - x + 2;

x^2 - 2x^2 + 3x + 2 + 5x - 2 = 0;

-x^2 + 8x + 0 = 0;

x^2 - 8x + 0 = 0;

3)(x + 3)(3x - 2)=(4x + 5)(2x - 3);

3x^2 - 2x + 9x - 6 = 8x^2 - 12x + 10x - 15;

3x^2 + 7x - 6 = 8x^2 - 2x - 15;

3x^2 - 8x^2 + 7x + 2x - 6 + 15 = 0;

-5x^2 + 9x + 9 = 0;

5x^2 - 9x - 9 = 0.