Найти корни уравнения 4х^2-547х+543=0

4x^2 - 547x + 543 = 0;

D = b^2 - 4ac;

D = (-547)^2 - 4 * 4 * 543 = 299209 - 8688 = 290521; √D = 539;

x = (-b ± √D)/(2a);

x1 = (-(-547) + 539)/(2 * 4) = (547 + 539)/8 = 1086/8 = 135,75;

x2 = (-(-547) - 539)/(2 * 4) = (547 - 539)/8 = 8/8 = 1.

Ответ. 1; 135,75.