3x+2y/5(3x-2y) при x=2/3 (дробь), y=0,75.

3x + 2y/5(3x - 2y)x=2/3, y=0,75= 75/100 = 15/20 = 3/43 * 2/3 + (2 * 3/4)/5(3 * 2/3 - 2 * 3/4) = 2 * 3/3 + (3 * 2/4)/5(2 * 3/3 - 3 * 2/4) = 2 * 1 + (3 * 1/2)/5(2 * 1 - 3 * 1/2) = 2 + 3/2 / 5(2 - 3/2) = 2 + 3/2 / 5(4/2 - 3/2) = 2 + 3/2 / 5(1/2) = 2 + 3/2 / 5/2 = 2 + 3/2 * 2/5 = 2 + 2/2 * 3/5 = 2 + 1 * 3/5 = 2 + 3/5 = 10/5 + 3/5 = 13/5 = 2 1/5 = 2 2/10 = 2,2Ответ: 2,2.