найдите производную функции: 1) y=x^3 - 2x^2+x+22) y= 1/x^2 3) y= 1/ cos x 4) y=( 3x^2-2 ) / x^35) y= tg x + 1/x

f(x)\' = ((-x^2 + 2x^2)^3 + (x - 3)^4)’ = ((-x^2 + 2x^2)^3)’ + ((x - 3)^4)’ = (-x^2 + 2x^2)’ * ((-x^2 + 2x^2)^3)’ + (x - 3)’ * ((x - 3)^4)’ = ((-x^2)’ + (2x^2)’) * ((-x^2 + 2x^2)^3)’ + ((x)’ – (3)’) * ((x - 3)^4)’ = (-2x + 4x) * (3 * (-x^2 + 2x^2)^2) + (1 - 0) * (4 * (x - 3)^3) = 2x * 3 * (x^2)^2 + 1 * (4 * (x - 3)^3) = 6x * x^4 + 4(x - 3)^3 = 6x^5 + 4(x - 3)^3.

f(x)\' = (sin^2 (x))’ = (sin (x))’ * (sin^2 (x))’ = cos (x) * 2 * sin^(2 – 1) (x) = cos (x) * 2 * sin^(1) (x) = cos (x) * 2 * sin (x) = 2cos (x) sin (x).

f(x)\' = (tg (x) - сtg (x))’ = (tg (x))’ – (сtg (x))’ = (1 / (cos^2 (x))) – (1 / (-sin^2 (x))) = (1 / (cos^2 (x))) + (1 / (sin^2 (x))).