Как найти производную функции: а) y = cosx - √3/2x б) y= 0,5 sin2x + sinx

1) f(х)\' = (sin^3 (2 - 3х))’ = (2 - 3х)’ * (sin (2 - 3х))’ * (sin^3 (2 - 3х))’ = ((2)’ – (3х)’) * (sin (2 - 3х))’ * (sin^3 (2 - 3х))’ = (0 – 3) * (соs (2 - 3х)) * 3 * (sin^2 (2 - 3х)) = (-3) * (соs (2 - 3х)) * 3 * (sin^2 (2 - 3х)) = (-9) * (соs (2 - 3х)) * (sin^2 (2 - 3х).

2) f(х)\' = (соs^2 (х / 3))’ = (х / 3)’ * (соs (х / 3))’ * (соs^2 (х / 3))’ = (1 / 3) * (-sin (х / 3)) * 2 * (соs (х / 3)) = (2 / 3) * (-sin (х / 3)) * (соs (х / 3)).