Тупой помогите решить: 5sin 360° + cos360° tg 0° + sin 180° – cos0° ctg60° – tg 30° sin 120° – cos60° sin 135° + cos 135° tg 120° : ctg 150°

5sin 360° + cos360° = 5•0+1 = 1tg 0° + sin 180° – cos0° = 0+0-1 = -1ctg60° – tg 30° = √3/3 - √3/3 = 0sin 120° – cos60° = √3/2 - 1/2 = (√3-1)/2sin 135° + cos 135° = √2/2 - √2/2 = 0 tg 120° : ctg 150° = -√3 /-√3 = -1