• sin(pi - a) - cos(pi/2 + a) + cos(pi - a) log 3 pi 2 -a) .

Ответы 1

  • sin(pi - a) - cos(pi/2 + a) + cos(pi - a) log 3 pi 2 -a)

    sin(pi - a) = sin(pi)cos(a) - cos(pi)sin(a) = 0 - (-1)sin(a) = sin(a)

    cos(pi/2 + a) = cos(pi/2)cos(a) - sin(pi/2)sin(a) = 0cos(a) - 1sin(a) = -sin(a)

    cos(pi - a) = cos(pi)cos(a) + sin(pi)sin(a) = -1cos(a) + 0sin(a) = -cos(a)

    sin(a) + sin(a) - cos(a) + log(3*pi/2 - a)

    2*sin(a) - cos(a) = sqrt(5)*sin(a - atan(2))

    sqrt(5)sin(a - atan(2)) + log(3pi/2 - a)

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