x+x+x=86 x+y+y=32 y-z=2 z-(x•y)=​

Ответ:

Let's solve the system of equations:

1. \(x + x + x = 86\) simplifies to \(3x = 86\).

2. \(x + y + y = 32\) simplifies to \(x + 2y = 32\).

3. \(y - z = 2\).

4. \(z - (x \cdot y) = ?\)

Starting with the first equation, \(3x = 86\), you can find the value of \(x\). Once you have \(x\), substitute it into the second equation to solve for \(y\). Then use \(y\) in the third equation to find \(z\). Finally, substitute \(x\), \(y\), and \(z\) into the fourth equation to determine the value of \(z - (x \cdot y)\).

Ответ:

дивись нижче

Пошаговое объяснение:

x+x+x=86

3х=86

х=86/3=28 2/3

x+y+y=32

х+2у=32

х=32-2у

або

у=(32-х)/2

y-z=2

у=2+z

або

z=y-2

z-(x•y)=​z-xy