решите уравнение 6*(b-3)=10-2*(b+2)_____________________________________


83+5*(y-3)=3*(8y-9)

6*(b-3)=10-2*(b+2)6b-18=10-2b-46b+2b=10-4+188b=24b=24/8b=36*(3-3)=10-2*(3+2)0=083+5*(y-3)=3*(8y-9)83+5y-15=24y-2783-15+27=24y-5y95=19yy=95/19y=583+5(5-3)=3(8*5-9)83+10=3*3193=93