Найти производные функции

№1
f(t)=0.5t3+0.6t2+0.8t+8 f '(1)-?

№2
y=4x 3/4 в степени + 3x 2/3 в степени + 4x 1/2 в степени + 3x

2) (3/4)*4x^(-91/4)+(2/3)*3x^(-1/3)+(1/2)*4x^(-1/2)+3=(3/(x^1/4))+(2/(x^1/3))+(2/(x^1/2))+3

1) 3*0,5t^2+2*0,6t+0,8=1,5t^2+1,2t+0,82) (3/4)*4x^(-1/4)+(2/3)*3x^(-1/3)+(1/2)*4x^(-1/2)+3=(3/(x^1/4))+(2/(x^1/3))+(2/(x^1/2))+3