Решить систему уравнений:

{
x+y=2,2
x^2+xy+y^2=8.

x+y=2,2x^2+xy+y^2=8.x=2,2-y(2,2-y)^2+(2,2-y)y+y^2=8.x=2,2-y4.84-4.4y+y^2+2.2y-y^2-8=0x=2,2-y2.2y-8=8-4.84x=2,2-yy=1.44x=2.2-1.44=0.76