найдите корни уравнения 2x^2+11x+34=(x+6)^2

2x^2+11x+34=(x+6)^2 2x^2+11x+34=x^2+12x+36 2x^2+11x+34-x^2-12x-36=0x^2-x-2=0 D = b2 - 4acD = 1 + 8 = 9 = 3^2x1,2 = -b ± √D/2ax1 = 1 + 3/2 = 4/2 = 2x2 = 1 - 3/2= - 2/2 = -1Ответ: x1 = 2; x2 = -1