(3sinx-5cos2x+1)/(8+7sin2x-2sin^2x)=0

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(3sinx-5cos2x+1)/(8+7sin2x-2sin²x)=08+7sin2x-2sin²x≠08sin²x+8cos²x-2sin²x+14sinxcosx≠08cos²x+6sin²x+14sinxcosx≠0 /2cos²x≠03tg²x+7tgx+4≠0tg²x=a3a²+7a+4≠0D=49-48=1a1≠(-7-1)/6≠-4/3⇒tgx≠-4/3⇒x≠-arctg4/3+πna2≠(-7+1)/6≠-1⇒tgx≠-1⇒x≠-π/4+πn3sinx-5cos2x+1=03sinx-5+10sin²x+1=010sin²x+3sinx-4=0sinx=b10b²+3b-4=0D=9+160=169b1=(-3-13)/20=-0,8⇒sinx=-0,8⇒x=(-1)^n+1*arcsin0,8+πnb2=(-3+13)/20=1/2⇒sinx=1/2⇒x=(-1)^n *π/6+πn