помогите в решении уравнения 2/7x+3/7x=2 7/14,если можно то подробно

а я думаю так...2/7x+3/7x=5/7x 5/7x=2 7/14 x=2 7/14:5/7 x=35/14:7/5 x=7/2 x=3 1/2

(x2-7x+3)^2+10(x2-7x+3)+21=0x2-7x+3=tt2+10t+21=0t12=(-10+-корень(100-84))/2=(-10+-4)/2=-7 -3x2-7x+3=-3x2-7x+6=0x12=(7+-корень(49-24))/2=(7+-5)/2=6 1x2-7x+3=-7x2-7x+10=0x34=(7+-коренб(49-40))/2=(7+-3)/2=5 2x= 1 2 5 6 (x^2 - 7x + 3)^2 + 10(x^2 - 7x + 3) + 21 = 0Пусть x^2 - 7x + 3 = tt^2 + 10t + 21 = 0D/4 = 25 - 21 = 4t1 = -5 + 2 = -3t2 = -5 - 2 = -7Выполним обратную замену:x^2 - 7x + 3 = -3                    или                        x^2 - 7x + 3 = -7x^2 - 7x + 6 = 0                                                  x^2 - 7x + 10 = 0D = 49 - 24 = 25                                                 D = 49 - 40 = 9x1 = (7+5)/2 = 6                                                 x3 = (7+3)/2 = 5x2 = (7-5)/2 = 1                                                  x4 = (7-3)/2 = 2Ответ: 1;2;5;6.я думаю так