решите логарифм

2lgx/lg(4x-3)=1

2lgx/lg(4x-3)=1log_{4x-3} (x²)=1x²=4x-3x²-4x+3=(x-1)(x-3)=0x=1, x=34x-3>0x>3/44x-3≠1x≠3/4x>0Отв: x=1, x=3

ОДЗ x>0 u 4x-3>0⇒x>3/4⇒x∈(3/4;∞)2lgx=lg(4x-3)lgx²-lg(4x-3)=0lgx²/(4x-3)=0x²/(4x-3)=1x²-4x+3=0x1+x2=4 U x1*x2=3x1=1 U x2=3