помогите найти корень уравнения, 7y-1\12-y+1\4=2y+5\3

7y-1/12 - y+1/4 =2y+5/3НОК (12,4,2)=12(7y-1)*12 -(y+1)*12 = (2y+5) *12____ ___ _____ 12 4 3 7y-1-3y+1=4(2y+5) 7y-1-3y+1=8y+20 7y-3y-8y=1-1+20 7y-3y-8y=20+4 -4y=24 y=24:(-4) y=-6

7y-1-3y+1=4(2y+5)7y-1-3y+1=8y+207y-3y-8y=1-1+207y-3y-8y=20+4-4y=24y=24:(-4)y=-6