Помогите!!!!!)

[tex] \frac{5y+1}{y+1} = \frac{y+2}{y} [/tex]

y(5y+1)=(y+1)(y+2)5y²+y=y²+2y+y+24y²-2y-2=02y²-y-1=0D=1+2*4=9=3²y(1)=(1+3)/2*2=4/4=1y(2)=(1-3)/4=-2/4=-1/2