Решите уравнение
4(х-4)(х+8)=(3х+2)(х-5)+(х-1)(х+1)

4(х-4)(х+8)=(3х+2)(х-5)+(х-1)(х+1);

4(x^2 - 4x + 8x - 32) = (3x^2 + 2x - 15x - 10) + (x^2 - x + x - 1);

4(x^2 + 4x - 32) = 3x^2 - 13x - 10 + x^2 - 1;

4x^2 + 16x - 128 = 4x^2 - 13x - 11;

16x + 13x = 128 - 11;

29x = 117;

x = 117/29 = 4 1/29;