{log√2 (x+y)=2 {3^x*7^x=21

log_√2 (x + y) = 2(3^x) * (7^x) = 21(3^x) * (7^x) = 21(21)^x = 21x = 1x = 1log_√2 (1 + y) = 2x = 11 + y = (√2)²x = 1y = 2 - 1x = 1y = 1Ответ:  (1;1)