Помогите решить.
5sin(2x-п/12)= -5

sin(2x -π/12) = -5/5sin(2x - π/12) = -12x - π/12 = -π/2 + 2πk, k∈Z2x=π/12  -π/2 + 2πk2x= -5π/12 +2πkx= -5π/24 + πk, k∈Z