решите уравнение: sin(x+пи/3)cos(x-пи/6)=1
Ответ: пи/6 + пиn

1/2*sin(x+π/3-x+π/6)+1/2sin(x+π/3+x-π/6)=11/2sinπ/2+1/2*sin(2x+π/6)=11/2*sin(2x+π/6)=1/2sin(2x+π/6)=12x+π/6=π/2+2πn,n∈z2x=-π/6+π/2+2πn,n∈z2x=π/3+2πn,n∈zx=π/6+πn,n∈z