найдите все корни уравнения :(6х+1)(6х-2)-(35х-1)(х+3)=10(5-11х)
решите уравнение:(2х-3)(2х+3)-(4х+5)(х-3)=-1
ЗА 7 КЛАСС
спасибо огромное вы мне очень поможите)
Предмет:
АлгебраАвтор:
sheenajoyce(2*X-3)*(2*X+3)-(4*X+5)*(X-3)=-1Ответ: 7+7*X=01) 4*X^2-9-(4*X+5)*(X-3)+1=0 1.1) (2*X-3)*(2*X+3)=4*X^2-9 (2*X-3)*(2*X+3)=2*X*2*X+2*X*3-3*2*X-3*3 1.1.1) 2*2=4 X2 _2_ 4 1.1.2) X*X=X^2 X*X=X^(1+1) 1.1.2.1) 1+1=2 +1 _1_ 2 1.1.3) 2*3=6 X2 _3_ 6 1.1.4) 3*2=6 X3 _2_ 6 1.1.5) 6*X-6*X=0 1.1.6) 3*3=9 X3 _3_ 92) 4*X^2-9-(4*X^2-7*X-15)+1=0 2.1) (4*X+5)*(X-3)=4*X^2-7*X-15 (4*X+5)*(X-3)=4*X*X-4*X*3+5*X-5*3 2.1.1) X*X=X^2 X*X=X^(1+1) 2.1.1.1) 1+1=2 +1 _1_ 2 2.1.2) 4*3=12 X4 _3_ 12 2.1.3) -12*X+5*X=-7*X 2.1.4) 5*3=15 X5 _3_ 153) 4*X^2-9-4*X^2+7*X+15+1=0 3.1) 4*X^2-9-(4*X^2-7*X-15)=4*X^2-9-4*X^2+7*X+154) -9+7*X+15+1=0 4.1) 4*X^2-4*X^2=05) 6+7*X+1=0 5.1) -9+15=6 -15 _ _9_ 066) 7+7*X=0 6.1) 6+1=7 +6 _1_ 7
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