Решить систему :
x-y=П/2
sinx+siny=√2

x-y=П/2 sinx+siny=√2 2sin[(x+y)/2]*cos[(x-y)/2]=√22sin[(x+y)/2]*cosπ/4=√22*√2/2*sin[(x+y)/2]=√2sin[(x+y)/2]=1(x+y)/2=π/2x+y=πx-y=π/22x=3π/2x=3π/4y=π/4