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Помогите пожалуйста) Выписаны первые несколько членов геометрической прогрессии: 1512; -252; 42; ... Найдите сумму первых четырех ее членов.
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Предмет:
Алгебра -
Автор:
simonecalderon - 6 лет назад
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Ответы 1
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q=42/-252=-1/6b4=42*(-1\6)=-7S4=1512+(-252)+42+(-7)=1295
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Автор:
erinboyd - 6 лет назад
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