4+(√x-4)=x Решите уравнение

ОДЗx ≥ 4 √(x - 4) = x - 4 x - 4 = (x - 4)^2x - 4 = x^2 - 8x + 16x^2 - 8x + 16 - x + 4 = 0 x^2 - 9x + 20 = 0 D = 81 - 80 = 1x1 = (9 + 1)/2 = 5;x2 = (9 - 1)/2 = 4;Ответ4; 5